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Mathematics 14 Online
OpenStudy (anonymous):

@aum

OpenStudy (anonymous):

Coke or Pepsi?

OpenStudy (anonymous):

wat

OpenStudy (anonymous):

nvmd

geerky42 (geerky42):

Do you know where discontinuity is? Can you "remove" it?

OpenStudy (anonymous):

is it -4?

OpenStudy (anonymous):

@waterineyes @Loser66 please help

OpenStudy (anonymous):

How can denominator become 0 ??

OpenStudy (anonymous):

if x is -2

OpenStudy (anonymous):

-2 ??

OpenStudy (anonymous):

0r -4

OpenStudy (anonymous):

-4?? You can take two more chances.. :P

OpenStudy (anonymous):

just -4!

OpenStudy (anonymous):

I PUT THE WRONG QUESTION UP

OpenStudy (anonymous):

OpenStudy (anonymous):

there we go , sorry

geerky42 (geerky42):

Ok, so you get denominator equal to 0. So you have \(x^2+6x+8=0\) Factoring will get us \((x+2)(x+4)=0\), so you are right. They are located at \(x=-2\) and \(-4\)

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