Question

help with trig integration ? Stuck on 1 step lol

Answer 1

\[\int\limits \sqrt{x^2-9}/(x)\]

Answer 2

@amistre64

Answer 3

i got stuck on integral 3tantheta *secthetatantheta/3sectheta

Answer 4

if u = sqrt(x^2-9)

du = 2x/2sqrt(x^2-9) dx

seems like things simplify to me

Answer 5

this is using trig sub

Answer 6

\[\int\limits \sqrt{x^2-9}/(x)~dx\]
\[\int\limits u~2\sqrt{x^2-9}/(x^2)~dx\]
\[\int\limits 2u^2/(\sqrt u-9)~dx\]

what trig sub did you try?

Answer 7

using the chain rule d/du=sin((e^u)(u^2))=dsinu/du where u=e^u(u^2)

Answer 8

x=3secTHETA dx = 3secTHETAtanTHETA

Answer 9

sin^2 - 1 = -cos^2

cos^2 - 1 = -sin^2

tan^2 = sec^2 - 1

all come to mind for the -1 part

Answer 10

Omg I just realized i made a dumb retricemistake thanks anyways!!

Answer 11

yeah, it does tend to be one of those mistakes :) i tend to make more of them on a test lol

Answer 12

Lmao same and then i just blank out after -_-

Answer 13

Welcome to Open Study!!

Answer 14

\[\sqrt{16-4\sin^2x}\]