looking for help with continuously compounded interest... how do you find initial investment and annual percent rate given the time to double is 7 yrs and amount after 10 yrs is 2400?
Some more good info: http://www.harpercollege.edu/mhealy/ecogif/uein/rule70.gif
\[\Large A=P e ^{rt}\]
i know the formula but I'm not sure how to find it
doubles in 7 years :\[\Large 2P = Pe^{r \cdot 7}\] solve for r
so r=9.9%?
right
thx so much!
how do i find the initial?
amount after 10 years is 2400 just plug in: A=2400 t=10 r= 0.09902 and solve for P
i divided 2400 by e^9.9 and it gave me a decimal
e^0.99
thanks again
Determine the time necessary for P dollars to double when it is invested at interest rate r compounded monthly, daily. r =3.4%
sorry I'm so lost;/
except you have to do extra since it's not a year but \[\frac{ 1 }{ 12 }th\] of a year and \[\frac{ 1 }{ 52 }\] of a year.
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