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OpenStudy (anonymous):
looking for help with continuously compounded interest... how do you find initial investment and annual percent rate given the time to double is 7 yrs and amount after 10 yrs is 2400?
11 years ago
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OpenStudy (paxpolaris):
\[\Large A=P e ^{rt}\]
11 years ago
OpenStudy (anonymous):
i know the formula but I'm not sure how to find it
11 years ago
OpenStudy (paxpolaris):
doubles in 7 years :\[\Large 2P = Pe^{r \cdot 7}\]
solve for r
11 years ago
OpenStudy (anonymous):
so r=9.9%?
11 years ago
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OpenStudy (paxpolaris):
right
11 years ago
OpenStudy (anonymous):
thx so much!
11 years ago
OpenStudy (anonymous):
how do i find the initial?
11 years ago
OpenStudy (paxpolaris):
amount after 10 years is 2400
just plug in:
A=2400
t=10
r= 0.09902
and solve for P
11 years ago
OpenStudy (anonymous):
i divided 2400 by e^9.9 and it gave me a decimal
11 years ago
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OpenStudy (paxpolaris):
e^0.99
11 years ago
OpenStudy (anonymous):
thanks again
11 years ago
OpenStudy (anonymous):
Determine the time necessary for P dollars to double when it is invested at interest rate r compounded monthly, daily. r =3.4%
11 years ago
OpenStudy (anonymous):
sorry I'm so lost;/
11 years ago
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OpenStudy (adamaero):
except you have to do extra since it's not a year but \[\frac{ 1 }{ 12 }th\]
of a year and \[\frac{ 1 }{ 52 }\] of a year.
11 years ago
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