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Mathematics 16 Online
OpenStudy (czarluc):

how to get the domain of composition of functions? or just steps...

OpenStudy (amistre64):

compositions are somewhat complicated the domain of the input function is altered so that the range of the function falls within the domain of the other function. then the range of the other function is adjusted to fit the inputs

OpenStudy (anonymous):

the domain of the compostion will be all of the input values of the inside function that leads to outputs of the inside function which are in the domain of the outside function.

OpenStudy (czarluc):

like what is the domainof this? Given f(x) = 3x2 + 2x − 1 and g(x) = 4x + 2, find [f º g](x)? f(4x + 2) = 3(4x + 2)2 + 2(4x + 2) − 1 = 3(16x2 + 16x + 4) + 8x + 4 − 1 = 48x2 + 56x + 15

OpenStudy (amistre64):

refresh clears the odd markers

OpenStudy (anonymous):

f, g... \[\left( f \circ g \right)\left( x \right) = f \left( g \left( x \right) \right)\] f is the outside functiona nd g is the inside function

OpenStudy (czarluc):

that's minus one sorry

OpenStudy (anonymous):

what's the domain of f?

OpenStudy (amistre64):

your f and g have no bad maths, and their composition causes no bad maths ... so the domain will remain the same

OpenStudy (czarluc):

it's R

OpenStudy (anonymous):

\(\mathbb{R}\)

OpenStudy (czarluc):

oh so just get the intersection of both?

OpenStudy (amistre64):

nothing in g makes f go bad ... so the domain of f(g) is the same as the domain of g

OpenStudy (anonymous):

and what's the domain and range of g?

OpenStudy (czarluc):

thanks for the reply guys... pg, it's d= R and R= R

OpenStudy (amistre64):

since pg is sounding more technical to me, and adequate as well, ill defer this to him :)

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