Question

@ganeshie8

Answer 1

@waterineyes

Answer 2

Use :

\[a^2-b^2 = (a-b)(a+b)\]

Answer 3

So this way:

\[x^2-9 = ?\]

Answer 4

Just replace a with x and b with 3..

Answer 5

@ganeshie8 i remember you explained it a different way before, i just dont remember

Answer 6

replace 9 by 3^2
and factor it using that difference of squares formula

Answer 7

\[\large x^2-9 = x^2 - 3^2 = (x+3)(x-3)\]

Answer 8

oh ok i got that, that was easy. just facorting the numberator

Answer 9

yes that factor `x-3` cancels the bottom factor

Answer 10

giving you just `x + 3`

Answer 11

take the limit now

Answer 12

so were just left with x+3

Answer 13

Oh ho, your way is different @ganeshie8 :P

Answer 14

idk how its different haha! yes 6 is the answer

Answer 15

thinking of a different problem @waterineyes. thank you @ganeshie8 your explanation was great

Answer 16

Really??

Answer 17

What have I said you??

Answer 18

I was just kidding wih ganesh not you..!!

Answer 19

ohh gotcha, i thought you were mocking me

Answer 20

Not at all.. :)

Answer 21

You said to him that his way is different than mine, that is why I was just pulling his leg.. :P