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OpenStudy (anonymous):
What mass (g) of barium iodide is contained in 250 mL of a barium iodide solution that has an iodide ion concentration of 0.193 M?
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OpenStudy (anonymous):
Is it \[BaI _{2}\]?
OpenStudy (anonymous):
Sorry, 0.193 / 250 = 0.000772 Moles BaI2 Then find the mass of BaI2 (137.33 + 2(126.9))
OpenStudy (anonymous):
And finally \[0.000772 * 391.13g \div 1Mole = 0.302g BaI2\]
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