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OpenStudy (anonymous):
subtract 1 from both sides
x/3=5
OpenStudy (anonymous):
then multiply both sides by 3.
OpenStudy (anonymous):
3(x/3)=5*3 which the 3s on x cancel out so x=15
OpenStudy (anonymous):
is it -5 or 5
OpenStudy (anonymous):
its wrong when u out the answer in the expression
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OpenStudy (texaschic101):
x/3 + 1 = -4 --- subtract 1 from both sides
x/3 = -4 - 1
x/3 = -5 -- multiply both sides by 3
x = -5(3)
x = -15
or
x/3 + 1 = -4 --- to get rid of fractions in an equation, multiply by the common denominaror, which is 3
(3)(x/3) + (3)1 = (3) -4
x + 3 = -12 -- subtract 3 from both sides
x = -12 - 3
x = -15
you can do it either way
OpenStudy (anonymous):
oh so sorry i thought it was positive 4
OpenStudy (anonymous):
so still subtract 1 from both sides so
OpenStudy (anonymous):
x/3=-3
OpenStudy (anonymous):
then multiply both sides by three to remove the 3 in the denominator on the right so x=-9
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OpenStudy (anonymous):
sorry!
OpenStudy (anonymous):
dangit i did it again
OpenStudy (anonymous):
...lololol
OpenStudy (anonymous):
x/3=-5
OpenStudy (anonymous):
its ok thx for your help I got it now
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