Question

will give medal. Find the points on the curve y = tan(x), -π/2 < x < π/2, where the tangent is parallel to the line y = 2x. Give all values correct to 3 decimal places.

Answer 1

your answer has a bunch of symbols so i cant see the answer..

Answer 2

im sorry, its doing it again :/

Answer 3

yeah 1 sec sorry

Answer 4

y=tan(x)
y=sec^2(x)

sec^2(x)=2
sec(x)=+- sqrt 2
cos(x)=+- 1sqrt2
so answers is (pi/4,1) (-pi/4_1)

Answer 5

Do you understand?

Answer 6

how is sec(x)= =-sqrt 2 ?

Answer 7

or + sqrt 2

Answer 8

i submitted my answers and it said they were wrong @n648c788

Answer 9

the answer is correct, just typo there, \(\dfrac{\sqrt 2}{2}\)
@lalalastudy how can it be wrong?

Answer 10

im not sure, they were all wrong except for the 1 in the first ordered pair

Answer 11

y' = sec^2 x =\(\dfrac{1}{cos^2x}\) and this y' =2 (because the line // y = 2x)

Answer 12

i mean the 1 in the second ordered pair

Answer 13

if 1 is correct, then -pi/4 must be correct , also , because if x = -pi/4, then tan x = 1
so as pi/4

Answer 14

alright i got them right!

Answer 15

thank you