Did I answer this question correctly?

the question is:

CH4 (methane) burns in oxygen (O2) to form carbon dioxide (CO2) and H2O

What mass of oxygen would you need to react with 8 dm^3 of methane? and what volume of carbon dioxide will be produced? ( All gas volumes are measured in 25 degree Celsius and 1 atp )

So what I did was:

write the balanced equation first:

CH4 + 2O2 —— CO2 + 2H2O

since 1 mole of any gas is 24 dm^3 at room temp. so for 8 dm^3 of methane should give 0.3 mole of CH4.

the Ratio between Methane and Oxygen = 1 : 2 = 0.3 mol x 2 = 0.6 mol of oxygen,

Question

Did I answer this question correctly?

the question is:

CH4 (methane) burns in oxygen (O2) to form carbon dioxide (CO2) and H2O
 
What mass of oxygen would you need to react with 8 dm^3 of methane? and what volume of carbon dioxide will be produced? ( All gas volumes are measured in 25 degree Celsius and 1 atp )

So what I did was:

write the balanced equation first:

CH4 + 2O2 ——> CO2 + 2H2O 

since 1 mole of any gas is 24 dm^3 at room temp. so for 8 dm^3 of methane should give 0.3 mole of CH4.

the Ratio between Methane and Oxygen =  1 : 2 =  0.3 mol x 2 = 0.6 mol of oxygen,

anonymous · Answer

So now I have mole and molar mass for oxygen, I can get the mass as:

Mass = 0.6 x (4 x 16)
= 38.4

as for CO2 it should be 8 dm^3 since its on a 1 : 1 ratio with Methane