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systems of equations: x+y=-2 3y+12=-6x Please explain the steps so that I can actually learn what I am doing. Thanks
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isolate one variable. in this case use the 1st equation to obtain y=-x-2. then use the variable y to replace "y" in the second equation: 3(-x-2)+12=-6x. solve for x.
i got x=-2 check your answer
yep i got x=-2
i got x=-2, then plugged it back in, and got 3y=0. I am sure that is not going to work. as the answer in the book says "only one solution"
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