alg2
First, I would graph the equation at www.desmos.com/calculator
I dont understand how to graph on that site
okay, hold on
okay
okay ..
now...graph the answer choices and see which one changes the vertex. there is an eaiser way to do this, but for the life of me i cannot remember it
I dont get how to graph it
Okay, let's take the first answer choice - f(x+4) This means do this: -f(x+4) = -[3((x+4)-3)^2]
so graph \[-(3(x+1)^2)\]
okay
did you graph it? if the graph of that equation has a different vertex than shown earlier, than that is the correct answer choice. If not, then we have to graph more
1,0 vertex?
Oh, I just realized something. I misread the question...
For each function written below you have to describe the change in the vertex (meaning all of them will change the vertex in some way)
You can still graph, but instead of choosing an answer choice, describe how the vertex is moved
if you are asking about -3(x+1)^2 to match that with a(x-h)^2 + k we write x+1 as x- -1 , and add +0 -3 (x - -1)^2 + 0 now we see h= -1 and k=0
yeah i have to figure out how they change
THANK YOU @phi I was trying to come up with a short cut to finding out of the vertex without graphing
but I totally forgot what is was... vertex = (h,k)
what is the original equation?
Okay, so if the vertex was originally (3,0), and with this equation it is (-1,0), what translation caused the vertex to move?
Basically you are describing the moves down/up and right/left that got it from (3,) to (-1,0)
(3,0) *
so how do i solve for the other one
in a formula method
im not good with the graphs
studygurl was showing how. (although once you figure it out, you can memorize the rules on how the function is shifted) for - f(x+4) there are two things you changed: you multiplied by -1 and you change x to x+4
in other words, you change f(x)= 3(x-3)^2+2 to -3 (x+4 - 3)^2 + 2 which simplifies to -3 (x- -1)^2 + 2 compare that to 3 (x - 3)^2 + 2
listen to @phi he/she is doing a better job lol. i have to go anyway
do you know what the vertex of the original equation is ?
in other words, match a (x - h)^2 + k with 3 (x - 3)^2 + 2 the vertex is at (h,k)
-3 and 2
you should match x - h x - 3 h is not -3
yes. next, we find the vertex of the "new version" -3 (x- -1)^2 + 2
match x with x - with - -1 with h
oops that should be a (x - h )^2 + k -3 (x - -1)^2 + 2
It's worth getting the hang of matching these formulas. It will help you.
yeah so the vertex would be postive 1,2
a vertex of 1,2 would come from a (x - h )^2 + k -3 (x - 1)^2 + 2 which is different from what we have.
but two - equals to a positive
yes, and that is what we use to rewrite (x+1) as (x - -1) the reason we want the second way is we want to match with (x - h) so we look for x. check look for minus sign. check look for number.... we see -1 the number is h
I still see the vertex being 1,2
ok. When I get into that way of thinking (that the answer is one way, but I'm told its not) then I back up and try to figure out what I am thinking that is wrong. (because I'm thinking something that is not true.) to help figure out what is going on (in your head), you should look at these -3 (x - -1)^2 + 2 h is -1 -3 (x - 1)^2 + 2 h is 1
okay ..
if you can't figure it out now, think about it later (Lots of times it clicks later) Meanwhile the original vertex is (3,2). the new vertex is (-1,2) which way did we move? and how far? any idea?
left 2 times
?
the y is the same (it's 2) so we do not move up/down the x changes from 3 to -1 what is the difference between 3 and -1? to find out we could count. 3,2,1,0,-1 (4 steps to the "left" i.e. towards the minus direction) or we could subtract 3 - (-1) = 4 either way, we get 4 (and it is to the left) we started with f(x) and changed to f(x+4) (ignore the minus sign for the moment) we changed the "x" which is a hint we moved sideways. the +4 means 4 steps sideways. the only thing that is confusing is +4 means we moved *left*
btw, if we change f(x) to f(x-4) that would be 4 steps to the *right* (This is confusing, but that is how it works)
ok so far?
yeah i already turned in the work thanks for helping me
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