y=(x/k)+k where k is constant tangent 4y=x^2, i) find k, ii) find P
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OpenStudy (freckles):
Are you wanting to find the tangent line to 4y=x^2?
OpenStudy (freckles):
You will need to first differentiate 4y=x^2?
OpenStudy (anonymous):
I need to find the value of constant K using the information above, i meant 4y=x^2 is the tangent to the curve y=(x/k)+k and joins the curve at point P, finding point P is the second part of the question where i just have to do simultaneous equations im pretty sure
OpenStudy (freckles):
Well I still think we need to differentiate 4y=x^2 to find the general slope formula and compare it to the slope of the line which is 1/k
OpenStudy (anonymous):
okay thanks
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OpenStudy (freckles):
Well have you done that yet?
OpenStudy (anonymous):
yup
OpenStudy (freckles):
which is?
OpenStudy (anonymous):
x/2
OpenStudy (freckles):
Ok so say we call the point that we want to find is (a,b)
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OpenStudy (freckles):
so the derivative evaluated at x=a is a/2
OpenStudy (freckles):
So we have a/2=1/k
OpenStudy (freckles):
So now solve that for k
OpenStudy (freckles):
just a picture if you think it would be helpful
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