Question

what would be the answer of ln ((e^a)/(e^b))? Thanks

Answer 1

Use the rule ln(a/b) = ln(a)-ln(b), then try to imagine what ln(e^a) and ln(e^b) will be.

Answer 2

Another method is: \(\ln\dfrac{e^a}{e^b}=\ln(e^{a-b})\), by a well-known rule for exponents.
Now you only need to think of what \(\ln(e^{a-b})\) is...

Answer 3

Thanks for the reply! so, if \[\ln (e ^{a-b})\] is equal to \[a-b \ln(e)\], it would be a-b?

Answer 4

Yes, that is correct! Just write it as: (a-b)ln(e) = a-b, otherwise your maths teacher will be unhappy...

Answer 5

Thank you!

Answer 6

YW!