) The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant.

2 HD(g) ⇌ H2(g) + D2(g) Kc = 0.28
6 H2(g) + 6 D2(g) ⇌ 12 HD(g) Kc = ?

A) 0.00048
B) 1.2
C) 1.62
D) 2075
E) 0.81
Answer: D

Question

) The equilibrium constant is given for one of the reactions below.  Determine the value of the missing equilibrium constant.

	2 HD(g)  ⇌  H2(g) + D2(g)  	Kc =  0.28
	6 H2(g) + 6 D2(g)  ⇌  12 HD(g)	Kc = ? 

A) 0.00048
B) 1.2
C) 1.62
D) 2075
E) 0.81
Answer:  D

ashley1nonly · Answer

ok since this one is a reverse we would use the 1/forward

ashley1nonly · Answer

im trying to figure out what the multiple would by to get them equal

anonymous · Answer

kk

ashley1nonly · Answer

they are both balanced

anonymous · Answer

kk 1 sec

anonymous · Answer

got it, so since reversed and multiplied by 6
1/.28^6

ashley1nonly · Answer

which side are we trying to get equal. the products or the reactants on the forward equation

ashley1nonly · Answer

never mind i see it, i just wasnt paying attention

anonymous · Answer

awseome! happens to me all the time, do you understand
so forward take number by exponent
reverse do 1/number by exponent

ashley1nonly · Answer

yes, i understand that. its very simple now that i understand.

i dont understand why my teacher just couldnt say that

anonymous · Answer

Teachers are mostly egotistic thats why haha

anonymous · Answer

Well im happy for you, anything else

ashley1nonly · Answer

ok i have one more im going to post

anonymous · Answer

kk