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So have you tried pluggin in as directed?
plug g into f and also plug f into g?
\[f(g(x))=f(\sqrt[3]{x-4}) \text{ means you will replace the x \in f with } \sqrt[3]{x-4}\]
Try replacing the x with the cuberoot(x-4) in f and simplify
simplify that the cube and cube root cancel
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\[f(g(x))=f(\sqrt[3]{x-4})=(\sqrt[3]{x-4})^3+4\]
Try simplifying f(g(x)) that I wrote above You should be confirming the results above that we will get x
then we will also have to do g(f(x))
is that it after that?
Yep you are just to confirm that f(g(x))=x and g(f(x))=x You must simplify both f(g(x)) and g(f(x)) and show they are both just equal to x.
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no no weneed to find their inverse and thn equate their inverse
They only want us to confirm that f and g are inverses
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