The base of a ten-foot ladder is being pushed away from the wall it is leaning against . If the base is moving at a rate of 2 feet per minute find the rate at which the top of the ladder is moving when the lower end of the ladder is 3 feet from the wall describe the significance of the sign of your results . discs s whether or not this sign depends on which side of the wall the ladder is leaning .
did you draw a picture?
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okay let me work it out
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no, h is not changing with time. (h is fixed at 10 ft., the length of the ladder).
2x*dx/dt=100
dh/dt = 0
\[x^2+y^2=h^2 \Rightarrow 2x \frac{ dx }{ dt }+2y \frac{ dy }{ dt }=0\]
they're asking for dy/dt
oh, so constant is 10 and the derivative of it is 0
how come the y isn't a constant?
look at the triangle... as x increases, y has to decrease because h stays constant.
oh... will y be sqrt 91 then?
yes... y = sqrt(100-9) = sqrt(91)
its a negative sign because the y is shrinking right?
yep
if the base is moving away from the wall then x is always increasing and subsequently, y will always be decreasing.
if the base moves towards the wall then x will be decreasing and in that case, y would be increasing.
oh~~~ I get it now xD
just get a 10' ladder and try the experiment... maybe use a strobe or slow motion video.
Alright! Thanks a lot!
you're welcome!
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