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A body of 200g is set to oscillate in an ideal spring. Knowing he performs two oscillations in 1 second, we can say that the spring constant is worth: a) 32 N/m b) 15 N/m c) 40 N/m d) 25 N/m e) 8 N/m
if a body of mass m oscillates on an ideal spring with spring constant k, then the frequency is given by \[f=\frac{ 1 }{ 2 \pi }\sqrt{\frac{ k }{ m }}\] which can fairly easily be derived using Newton's second law and the assumption of an oscillatory motion Rearrange this equation to find k in terms of f and m
could teach me step by step?
multiply both sides by 2pi square both sides multiply both sides by m
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