Question

Differentiate.
y= sec 0 tan 0

Answer 1

\[y=\sec \theta \tan \theta \]

Answer 2

use the product rule...

Answer 3

\[\text{if }y=u \cdot v \text{ then }y\,'=u'\cdot v + u \cdot v\,'\]

Answer 4

I keep getting the wrong answer

Answer 5

what do you get?

Answer 6

\[\sec \theta (\tan ^{2}\theta) + \sec ^{2} (\theta)\]

Answer 7

\[\left[\sec \left( \theta \right)\tan\left( \theta \right)\right]\tan \left( \theta \right)+\sec \left( \theta \right)\left[ \sec^2\left( \theta \right) \right]=\sec \left( \theta \right)\tan^2\left( \theta \right)+\sec^3\left( \theta \right)\]