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Mathematics 20 Online
OpenStudy (anonymous):

Give the equation of the function g whose graph is described. The graph of f(x) = |x| is vertically stretched by a factor of 4.5. This graph is then reflected across the x-axis. Finally, the graph is shifted 0.47 units downward.

OpenStudy (anonymous):

Sup sup sup!

OpenStudy (anonymous):

haha hey just the usual

OpenStudy (anonymous):

that's good...alrighty lets take a look at this.

OpenStudy (anonymous):

alright

OpenStudy (anonymous):

Ah so it's a transformation problem, do you know how to start this?

OpenStudy (anonymous):

verrtically stretched so on the y axis, and then it's reflection makes it -4.5 then the shift dow is -.47

OpenStudy (anonymous):

yup we need to take it one step at a time, so how do we stretch ƒ(x) = |x| by 4.5 vertically?

OpenStudy (anonymous):

f(x) is what the ????? are

OpenStudy (anonymous):

y?

OpenStudy (anonymous):

a vertical stretch is a stretch away from the x

OpenStudy (anonymous):

well no. a vertical stretch is just a vertical stretch as if the graph you are graphic on was made of clay and you streched while the function was written on it

OpenStudy (anonymous):

oh ok then, right

OpenStudy (anonymous):

so do you know how stretch something vertically on a graph using mathematical manipulations?

OpenStudy (anonymous):

no i dont think i do

OpenStudy (anonymous):

that's fine! Let's learn about it now! So to vertical manipulate an equation all we need to do it multiple whatever y's equal to by a value. So for example:\[y = x\] to stretch that by 10 times we do this:\[y=10 \times x\]Do you have a graphing calculator? If so plot these two equations.

OpenStudy (anonymous):

yeah i do

OpenStudy (anonymous):

so do you see how y=x looks like it was stretched by a factor of 10?

OpenStudy (anonymous):

i graphed them

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

nice so now you know how to stretch and shrink things vertically! right?

OpenStudy (anonymous):

right

OpenStudy (anonymous):

ok so question do you want to know further manipulations or just the ones in the problem?

OpenStudy (anonymous):

ok one more then problem

OpenStudy (anonymous):

ok hmmm let's go with horizontal streching

OpenStudy (anonymous):

to horizontally stretch a function all we need to do is mulitply x with a value but a bigger number compresses it while a smaller number stretches it: so instead of thing that the y=x was vertically stretched you could have thought of it as being compressed horizontally, does this make sense?

OpenStudy (anonymous):

umm kinda o instead of thing that the y=x was vertically stretched you could have thought of it as being compressed horizontally, does this make sense? this part ????

OpenStudy (anonymous):

you don't get that part?

OpenStudy (anonymous):

no not that part

OpenStudy (anonymous):

haha ok let's see, if I can put it another way. so you graphed y = x and y = 10x right?

OpenStudy (anonymous):

yeah

OpenStudy (aum):

Vertical stretching implies the graph is getting pulled away from the x-axis. When you pull something away from the x-axis you are making it closer to the y-axis which implies horizontal compression.

OpenStudy (anonymous):

exactly what aum said does that make sense?

OpenStudy (anonymous):

yes it does

OpenStudy (aum):

|dw:1413423765470:dw|

OpenStudy (anonymous):

nice cool alright so lets move on to the next part of the problem: the graph is reflected across the x-axis. To do this you simply need to multiply y by -1 so if: \[y = (x-3)\] and you want to reflect this across the x axis we simply do this: \[y = -1 \times (x-3)\] does that make sense?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

alrighty the last part says that it was shifted downward which if I remember correctly you know how to do?

OpenStudy (anonymous):

I just realized that you said that whole thing...sorry I was helping another person...do you have an answer to this problem actually?

OpenStudy (anonymous):

its ok i was reading it

OpenStudy (anonymous):

wait so do you know how to manipulate the equation?

OpenStudy (anonymous):

haha and you would be dead on correct!

OpenStudy (anonymous):

oh yes!

OpenStudy (anonymous):

next one?

OpenStudy (anonymous):

yup the next one!

OpenStudy (anonymous):

do you know how to do this?

OpenStudy (anonymous):

i graphed it and wherever it crosses y?

OpenStudy (anonymous):

well no a vertical asymptote is when function head off to infinity (either negative or positive) in the middle of the function. And there's a way to tell from just the equation itself!

OpenStudy (anonymous):

want to know how?

OpenStudy (anonymous):

yes of course

OpenStudy (anonymous):

haah ok here it is whenever the function attempts to divide by 0, is where a vertical asymptote can lie.

OpenStudy (anonymous):

does that make sense?

OpenStudy (anonymous):

9 and -8?

OpenStudy (anonymous):

yup!! Correct! now there's a reason as to why I said can instead of will, want to know why?

OpenStudy (anonymous):

no need to ask, of course

OpenStudy (anonymous):

haha because imagine if in this problem alongside (x-5) we had a (x+8) so the function would be: \[\frac{(x-5)(x+8)}{(x-9)(x+8)}\] there actually wouldn't be a asymptote at x =-8 but rather there would be something called a hole. Do you know what a hole is?

OpenStudy (anonymous):

ummm a parabola on both sides of x intercept?

OpenStudy (anonymous):

umm no... did you graph this function?

OpenStudy (anonymous):

or rather graph this function and the problem's if you haven't already

OpenStudy (anonymous):

give me a sec

OpenStudy (anonymous):

|dw:1413426004918:dw|

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