Give the equation of the function g whose graph is described. The graph of f(x) = |x| is vertically stretched by a factor of 4.5. This graph is then reflected across the x-axis. Finally, the graph is shifted 0.47 units downward.
Sup sup sup!
haha hey just the usual
that's good...alrighty lets take a look at this.
alright
Ah so it's a transformation problem, do you know how to start this?
verrtically stretched so on the y axis, and then it's reflection makes it -4.5 then the shift dow is -.47
yup we need to take it one step at a time, so how do we stretch ƒ(x) = |x| by 4.5 vertically?
f(x) is what the ????? are
y?
a vertical stretch is a stretch away from the x
well no. a vertical stretch is just a vertical stretch as if the graph you are graphic on was made of clay and you streched while the function was written on it
oh ok then, right
so do you know how stretch something vertically on a graph using mathematical manipulations?
no i dont think i do
that's fine! Let's learn about it now! So to vertical manipulate an equation all we need to do it multiple whatever y's equal to by a value. So for example:\[y = x\] to stretch that by 10 times we do this:\[y=10 \times x\]Do you have a graphing calculator? If so plot these two equations.
yeah i do
so do you see how y=x looks like it was stretched by a factor of 10?
i graphed them
yes
nice so now you know how to stretch and shrink things vertically! right?
right
ok so question do you want to know further manipulations or just the ones in the problem?
ok one more then problem
ok hmmm let's go with horizontal streching
to horizontally stretch a function all we need to do is mulitply x with a value but a bigger number compresses it while a smaller number stretches it: so instead of thing that the y=x was vertically stretched you could have thought of it as being compressed horizontally, does this make sense?
umm kinda o instead of thing that the y=x was vertically stretched you could have thought of it as being compressed horizontally, does this make sense? this part ????
you don't get that part?
no not that part
haha ok let's see, if I can put it another way. so you graphed y = x and y = 10x right?
yeah
Vertical stretching implies the graph is getting pulled away from the x-axis. When you pull something away from the x-axis you are making it closer to the y-axis which implies horizontal compression.
exactly what aum said does that make sense?
yes it does
|dw:1413423765470:dw|
nice cool alright so lets move on to the next part of the problem: the graph is reflected across the x-axis. To do this you simply need to multiply y by -1 so if: \[y = (x-3)\] and you want to reflect this across the x axis we simply do this: \[y = -1 \times (x-3)\] does that make sense?
yes
alrighty the last part says that it was shifted downward which if I remember correctly you know how to do?
I just realized that you said that whole thing...sorry I was helping another person...do you have an answer to this problem actually?
its ok i was reading it
wait so do you know how to manipulate the equation?
haha and you would be dead on correct!
oh yes!
next one?
yup the next one!
do you know how to do this?
i graphed it and wherever it crosses y?
well no a vertical asymptote is when function head off to infinity (either negative or positive) in the middle of the function. And there's a way to tell from just the equation itself!
want to know how?
yes of course
haah ok here it is whenever the function attempts to divide by 0, is where a vertical asymptote can lie.
does that make sense?
9 and -8?
yup!! Correct! now there's a reason as to why I said can instead of will, want to know why?
no need to ask, of course
haha because imagine if in this problem alongside (x-5) we had a (x+8) so the function would be: \[\frac{(x-5)(x+8)}{(x-9)(x+8)}\] there actually wouldn't be a asymptote at x =-8 but rather there would be something called a hole. Do you know what a hole is?
ummm a parabola on both sides of x intercept?
umm no... did you graph this function?
or rather graph this function and the problem's if you haven't already
give me a sec
|dw:1413426004918:dw|
Join our real-time social learning platform and learn together with your friends!