Question

help me find the derivative of x3^x/3x-1

Answer 1

x3^x ?

Answer 2

do i bring the x down or what?

Answer 3

yeah

Answer 4

sorry i mean (x3^x)/3^(x)-1

Answer 5

\[\frac{d}{dx}\left[\frac{x3^x}{3^x-1}\right]\]

Answer 6

is that right ^

Answer 7

yep that correct

Answer 8

have you studied ln ?

Answer 9

yeah but i still dont get it :(

Answer 10

Some tools you'll need:
\[\textbf{Product rule}\\\textbf{Quotient rule}\\
\textbf{Derivatives of exponential function}\text{, i.e. }\frac{d}{dx}e^x=e^x\]

Answer 11

so you use the quotient rule and e on this one?

Answer 12

e^x = e^x is special case

Answer 13

ok it's really simple

Answer 14

I mean for bases other than \(e\), you can still use the derivative form of \(e^x\).
\[b^x=e^{\ln b^x}=e^{x\ln b}~~\implies~~\frac{d}{dx}b^x=\ln b\cdot e^{x\ln b}=\ln b\cdot b^x\]

Answer 15

so it would be 3e^x

Answer 16

https://awwapp.com/draw.html#ce7077cd

Answer 17

click on the link it will lead you to whiteboard. we will solve it there

Answer 18

let me know when you are in

Answer 19

i am there