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OpenStudy (anonymous):
finding the eigen value
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OpenStudy (anonymous):
\[\lambda(\lambda-4)(\lambda-3)+7-9(\lambda-4)-(\lambda-3)=0\]
OpenStudy (anonymous):
@lawls
OpenStudy (dan815):
uhhh
OpenStudy (dan815):
guess
OpenStudy (anonymous):
\[\lambda = .... ,. ..??\]
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OpenStudy (dan815):
what was ur matrix
OpenStudy (dan815):
i wanna see how u got that 7 there
OpenStudy (dan815):
check 2 and -2
ganeshie8 (ganeshie8):
are you trying to diogonalize ?
OpenStudy (kainui):
Why not distribute everything and make it of the form \[\LARGE a \lambda ^3+b \lambda^2+c \lambda + d=0\]
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OpenStudy (kainui):
You can then graph it on your calculator and use that to essentially "guess" the factors.
ganeshie8 (ganeshie8):
there seems to be something wrong.. usually the matrix is cooked up such that the characteristic eq'n is easily solvable..
OpenStudy (gorv):
\[\lambda( \lambda^2-7*\lambda+12)+7-9\lambda+36-\lambda+3\]
OpenStudy (gorv):
\[\lambda^3-7*\lambda^2+12*\lambda+7-10\lambda+46=0\]
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OpenStudy (gorv):
\[\lambda^3-7\lambda^2+2\lambda+53=0\]
OpenStudy (gorv):
\[\lambda=-2.28, 4.64 , 4.64\]
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