Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

finding the eigen value

OpenStudy (anonymous):

\[\lambda(\lambda-4)(\lambda-3)+7-9(\lambda-4)-(\lambda-3)=0\]

OpenStudy (anonymous):

@lawls

OpenStudy (dan815):

uhhh

OpenStudy (dan815):

guess

OpenStudy (anonymous):

\[\lambda = .... ,. ..??\]

OpenStudy (dan815):

what was ur matrix

OpenStudy (dan815):

i wanna see how u got that 7 there

OpenStudy (dan815):

check 2 and -2

ganeshie8 (ganeshie8):

are you trying to diogonalize ?

OpenStudy (kainui):

Why not distribute everything and make it of the form \[\LARGE a \lambda ^3+b \lambda^2+c \lambda + d=0\]

OpenStudy (kainui):

You can then graph it on your calculator and use that to essentially "guess" the factors.

ganeshie8 (ganeshie8):

there seems to be something wrong.. usually the matrix is cooked up such that the characteristic eq'n is easily solvable..

OpenStudy (gorv):

\[\lambda( \lambda^2-7*\lambda+12)+7-9\lambda+36-\lambda+3\]

OpenStudy (gorv):

\[\lambda^3-7*\lambda^2+12*\lambda+7-10\lambda+46=0\]

OpenStudy (gorv):

\[\lambda^3-7\lambda^2+2\lambda+53=0\]

OpenStudy (gorv):

\[\lambda=-2.28, 4.64 , 4.64\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!