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Mathematics 19 Online
OpenStudy (anonymous):

how to find restrictions for a literal equation? example: (a+x)/(b-x) =c , x=/=b note: when writing the restrictions, x cannot be part of the restriction because it is the variable we are solving for...(so we do substitution to avoid that??) can someone show the substitution part?

OpenStudy (anonymous):

solve for x

OpenStudy (freckles):

So we are solving for x. You can multiply both sides by (b-x) as a first step Bur out goal is to eventually gather x terms on one side and non-x terms on the opposite side

OpenStudy (freckles):

\[a+x=c(b-x)\] distribute the c

OpenStudy (freckles):

then again gather the x terms on one side and the non-x terms on the other

OpenStudy (anonymous):

how would you find restrictions?

OpenStudy (anonymous):

i know that the answer is x= (cb-a)/c+1 and the restriction is c=-1 and x cannot equal b but the problem is that x=/=b cannot be part of the solution because we are using the variable that we are solving for. therefore, we have to substitute the solution in the x=/=b. so we solve (cb-a)/(c+1) =/= b after this im stuck. do we simplify? or can we leave the restriction just like that?

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