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Chemistry 18 Online
OpenStudy (anonymous):

how cn we calculate the volume of h2 if we know it's diameter?

OpenStudy (anonymous):

h2 was supposed to be H2 for hydrogen gas

OpenStudy (anonymous):

so the diamter i got is 0.000024

OpenStudy (anonymous):

would someone please help me

OpenStudy (aaronq):

you want the volume of the molecule?

OpenStudy (anonymous):

yeah would i use v=nRT/p ? also, the diameter is 0.000024 in cm

OpenStudy (aaronq):

nope, that's only used for bulk gases. If you're approximating the volume of single \(H_2\) molecule, you can model it as a known shape, like a cylinder.

OpenStudy (anonymous):

ok, thanks :)

OpenStudy (aaronq):

no problem. This isn't for a quantum mechanics class though, is it?

OpenStudy (anonymous):

so @aaronq i would try to solve for it by using the volume of cylinder formula? Just to make sure

OpenStudy (anonymous):

No, it's just chemistry

OpenStudy (anonymous):

but this was assigned from the professor

OpenStudy (anonymous):

he came up with the question

OpenStudy (aaronq):

we'll it depends what you model it as, it could also be modelled as a sphere, or a combination of cylinder-hemispheres

OpenStudy (anonymous):

This is how he wrote it "Postive (higher) deviation from ideal gas is due to volume of molecules themselves. If H2 has a diameter of 2.4x10^-8 cm what is it's volume? What is the volume in 1 mole of H2 molecules?

OpenStudy (anonymous):

he never told the class what model to use....

OpenStudy (anonymous):

i would have to multiply Avogadro number by the molar mass of H2 but didn't get the diameter part

OpenStudy (aaronq):

ohh, then i think he wants it modelled as a sphere. for the second part, where he wants the volume of a mole, it's a bit harder. you could make the assumption that there is no space between them and try to pack the spheres next to one another

OpenStudy (aaronq):

this type of thing i imagine http://en.wikipedia.org/wiki/Close-packing_of_equal_spheres

OpenStudy (anonymous):

So i would use the volume of a sphere to calculate the first one. V=4/3(pi)r^3 ok, the second part i would just have to make assumption based off of that "Close-packing of equal spheres" and no math involved?

OpenStudy (aaronq):

Yes for the first part. For the second, you need to use some math obviously lol but there are formulas worked out for you, find the volume of a unit cell, then multiply that unit cell to account for all the atoms. remember we're assuming that the molecules are touching each other, which would only happen in a solid

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