Question

Medal and fan!

Find the values of x and y that minimize the objective function C = 3x+4y for the constraints below.

Just need someone to check my work. :)

Answer 1

\[x+y \ge8\]
\[x+5y \ge20\]
\[x \ge0,y\]

Answer 2

They told me to find the slope-intercept, so I did:
\[y \ge-x+8\]
\[y \ge-\frac{ x }{ 5 }+4\]

Answer 3

did you graph that

Answer 4

yep
https://www.desmos.com/calculator/b3bhpxbiz0

Answer 5

Is that right? The coordinates I mean.

Answer 6

let me see it

Answer 7

Clink on the link.

Answer 8

why did you put y>2

Answer 9

I don't know why OS is being so buggy, but I meant \[y \ge2\]

Answer 10

yeah that is

Answer 11

Because that is one of the constraints

Answer 12

where i didn't seen that on the top

Answer 13

So are the vertices correct: (5,3),(6,2),(10,2)?

Answer 14

well if y>2 then yes
but i didn't see that in the constraints

Answer 15

Yeah I know: I made a typo. And thanks for your help :) I got the rest

Answer 16

no actually that is not right

Answer 17

oh. I kind of thought so :( it didn't seem to intersect correctly.
what would it be then?

Answer 18

because it should be where you have all shade and blue shade is not one of them

Answer 19

yeah that's what I thought

Answer 20

look this one
now you can look that

Answer 21

your point are where you even not have blue shade

Answer 22

That's weird...I don't see a point where they intersect...

Answer 23

i'm looking for that

Answer 24

It can't be (0,4),(0,8),(5,3) either right? Then the red wouldn't intersect.

Answer 25

nope than there is not red shade

Answer 26

Hmm...I'll probably have to contact my teacher >.< this is unsolvable

Answer 27

(0,8) ( 5 , 3)
( 10 ,2) is one of corner points

Answer 28

Ah, I see. So maybe (0,2),(0,8),(5,3),(10,2) are the vertices?

Answer 29

Like this: https://www.desmos.com/calculator/cw4ugzj2at

Answer 30

no 0,2 is absolutely not one of corner because corner point is where all shade you have

Answer 31

0,2 is only contain one line which is y > 2

Answer 32

what about (6,2)

Answer 33

Actually no, then the blue wouldn't intersect.

Answer 34

nope ohh yep you got that

Answer 35

are you sure y>2

Answer 36

isn't that suppose to be y>0

Answer 37

Yeah. I checked for typos and everything is perfect :(

Answer 38

No. y is 2, no doubt.

Answer 39

And it actually threw me off since I actually thought it was 0 at first.

Answer 40

ok so your point are ( 0,8) ( 5 , 3)
( 10 ,2)
and also you have to find minimize number so i think one of these point should work because all other point are increase value of y and x

Answer 41

yeah, I'll just input y and x in 3x+4y to determine the minimum value :( I just hope this is right

Answer 42

But, forget it. I really don't care if she takes a point off or two for not getting all the points right. I'll probably just close this in a minute.

Answer 43

look this graph where i mark red that all shaded region because all line are going this site so its absolutely increasing ( hope so its work )

Answer 44

ok. thanks for your help :)

Answer 45

ok best of luck for that
if i'm wrong sorry for that in advance
best of luck
let me know when you confirm that

Answer 46

well its my pleasure to help that i didn't exactly