HELP???
the hubble space telescope was deployed on April 24, 1990, by the space shuttle discovery. A model for the velocity of the shuttle during this mission, from liftoff at t=0 until the solid rocket boosters were jettisoned at t=126 is given by v(t)=0.001302t^3 - 0.09029t^2 +23.61t - 3.083 (in feet per second). Using this model, estimate the absolute maximum and minimum values of the acceleration of the shuttle between liftoff and the jettisoning of the boosters.

Question

HELP???
the hubble space telescope was deployed on April 24, 1990, by the space shuttle discovery. A model for the velocity of the shuttle during this mission, from liftoff at t=0 until the solid rocket boosters were jettisoned at t=126 is given by v(t)=0.001302t^3 - 0.09029t^2 +23.61t - 3.083 (in feet per second). Using this model, estimate the absolute maximum and minimum values of the acceleration of the shuttle between liftoff and the jettisoning of the boosters.

perl · Answer

the acceleration is the derivative of velocity

perl · Answer

a(t) = v'(t)

perl · Answer

v(t)=0.001302t^3 - 0.09029t^2 +23.61t - 3.08 
v ' (t) = 0.00130*3*t^2 - 0.09029*2*t + 23.61

anonymous · Answer

Then how do i find the minimum and maximum?

anonymous · Answer

im confused

perl · Answer

sorry if i confused you. here is the answer http://webcache.googleusercontent.com/search?q=cache:AQY6OGmewvcJ:web.cs.du.edu/~sbutz/calculus/winter_quarter/2q1an7.tex+&cd=3&hl=en&ct=clnk&gl=us&client=firefox-a