Question

(6-7i)/(-10+2i)

Answer 1

you know what the conjugate of
\(-10+2i\) is ?

Answer 2

is it -10-2i?

Answer 3

yes

Answer 4

multiply top and bottom by \(-10+2i\)
and the reason this works is that
\[(a+bi)(a-bi)=a^2+b^2\] a real number

Answer 5

you don't multiply by the conjugate?

Answer 6

the denominator will be
\[10^2+2^2=104\]
the numerator will be whatever you get when you multiply
\[(6-7i)(-1+2i)\]

Answer 7

thank you

Answer 8

yw
typo on that last line though

Answer 9

yeah I noticed that, I figured

Answer 10

the answer key says -37+29i/52 I am not getting that and that's not what you said

Answer 11

would you like help with this?

Answer 12

yes