Question

please check my answer i think its b

Answer 1

if 32 is the speed for chuck then dana goes 27 (5 less than chuck)

using
speed * time= distance
time = distance/speed

chuck took 117/32
dana took 102/27

the time's are supposed to be equal? Are they?

Answer 2

if we say "x" is how fast chuck went
then the time he went (using time = distance/speed) is
time= 117/x

if chuck goes x, dana goes x-5 (5 mph slower, right?)
dana's time = 102/(x-5)

they spent the same amount of time so set the times equal
\[ \frac{117}{x} = \frac{102}{(x-5)} \]
to solve for "x" (speed of chuck) you could first "cross-multiply"

Answer 3

46 seems to be the closest

Answer 4

sorry 39
thanks for the help