suppose you roll 2 dies find probability of not rolling a sum of 8

Question

geerky42 · Answer

How many outcomes of a roll that sum up to be 8?

anonymous · Answer

1+7 7+1 2+6 6+2 4+4 5+3 3+5 , so 7

anonymous · Answer

, so 28/36

anonymous · Answer

and that simplifies to 7/9 ..... am I right? i sure hope so, because It took me this long to figure this all out

anonymous · Answer

@Jesstho.-. @Lyrae

anonymous · Answer

@jdoe0001

anonymous · Answer

@ganeshie8

kropot72 · Answer

The number of dots on a die usually ranges from 1 up to a maximum of 6.
The sample space has 36 possible combinations of numbers. These can be set out in column form as follows: 
6,6   5,6   4,6   3,6   2,6   1,6
6,5   5,5   4,5   3,5   2,5   1,5 
6,4   5,4   4,4   3,4   2,4   1,4 
6,3   5,3   4,3   3,3   2,3   1,3 
6,2   5,2   4,2   3,2   2,2   1,2 
6,1   5,1   4,1   3,1   2,1   1,1 
This table shows 5 pairs that sum up to 8. Therefore the probability of not rolling a sum of 8 is given by:
$$\large \frac{36-5}{36}=you\ can\ calculate$$