Question

A solution is made by dissolving 25.5 grams of glucose (C6H12O6) in 398 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.

Answer 1

Well, you already know the freezing point constant, so all you need to do is find molal concentration of the \(solution\). Keeping in mind that molality is: \(\sf \frac{moles~of~solute}{kg~of~solvent}\)

Answer 2

\(\sf \Delta T_f = K_f \times m\)