Write the equation of the line with a slope of -1/3 and passing through the point (6, -4).

Question

camerondoherty · Answer

Ummm
y = 1/3x - 4
I think... Not 100% sure though
Its in SLope Intercept Form btw
Y=Mx+B

anonymous · Answer

$$y-y _{1}=m(x-x _{1})$$

shadowlegendx · Answer

y = mx + b
y = -1/3x - 4

shadowlegendx · Answer

This is the equation of the line as it shows the slope, -1/3 and also the y-intercept, -4. This equations tells you where you need to start on the y axis if you are to graph this line and at what rise/run the line will be at.

anonymous · Answer

I get it now, and thank you. Can you help me with a couple more that are similar to this one?

anonymous · Answer

$$y-(-4)=\frac{ -1 }{ 3 }\left( x-6) \right)$$
or 3(y+4)=-1(x-6)
3y+12=-x+6
3y=-x+6-12
3y=-x-6
$$y=-\frac{ 1 }{ 3 }x-2$$

anonymous · Answer

put x=6,y=-4
$$-4=\frac{ -1 }{ 3 }*6-2=-2-2~or~-4=-4$$
which is true .
Hence point (6,-4)lies on this line and slope is -1/3