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Calculus1 32 Online
OpenStudy (anonymous):

Stuck on a problem finding where a function is increasing or decreasing f(x)=5sin^2x on interval [-pi,pi] I know the derivative f'(x)=10sinxcosx and then set it = 0 10sinxcosx=0 that is where im stuck because you cant divide or move anything and im not sure how to approach the problem

OpenStudy (perl):

to find where the function is increasing, you solve f ' (x) > 0

OpenStudy (perl):

f ' (x) = 0 gives you just the x value where f has a slope of zero

OpenStudy (perl):

you want to find x values where f ' (x) is positive (so f is increasing) and x values where f ' (x) is negative ( so f is decreasing)

OpenStudy (anonymous):

so 10cosxsinx > 0 and then plug in variables until i find one that gives a value greater than 0 and a value less than 0?

jimthompson5910 (jim_thompson5910):

set 10*cos(x)*sin(x) equal to zero and solve for x. Once you get the roots of the equation, you can figure out what values to test (so you can see which parts are above the x axis)

OpenStudy (anonymous):

thats where im not sure how to approach the problem. i set it = 0 and then the only thing i can do would be to divide and if i do that i would just get 0=0

jimthompson5910 (jim_thompson5910):

10*cos(x)*sin(x) = 0 cos(x) = 0 or sin(x) = 0 solve each piece for x

jimthompson5910 (jim_thompson5910):

use the unit circle

jimthompson5910 (jim_thompson5910):

keep your interval of [-pi, pi] in mind

OpenStudy (anonymous):

OHHH ok i didnt even think to break it apart like that, give me a minute to work it

OpenStudy (anonymous):

So for sinx it would be x=0 and for cosx it would be x = -pi/2 and pi/2 i googled a picture of a unit circle and i am pretty sure that is correct

jimthompson5910 (jim_thompson5910):

there's one more solution to sin(x) = 0

OpenStudy (anonymous):

positive pi?

jimthompson5910 (jim_thompson5910):

-pi as well, sorry 2 other solutions

jimthompson5910 (jim_thompson5910):

so you have these 5 roots in [-pi, pi] -pi, -pi/2, 0, pi/2, pi

OpenStudy (anonymous):

so there is two for cosx which are -pi/2 and pi/2 and three for sinx are -pi 0 pi

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

those are your boundary points so to speak

jimthompson5910 (jim_thompson5910):

anything in between needs to be tested (one value per region) to see if 10*cos(x)*sin(x) > 0 is true or not

OpenStudy (anonymous):

and thats where i would plug in values from inbetween those points to determine if it is increasing or decreasing at certain intervals

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

I recommend a sign chart

jimthompson5910 (jim_thompson5910):

this page explains it a bit more with actual visual graphs to show http://www.purplemath.com/modules/ineqsolv3.htm

OpenStudy (anonymous):

if i could give more than 1 best response i would thanks for the pointers. im going to have to do a little review on the unit circle. but thanks for the help

jimthompson5910 (jim_thompson5910):

np

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