Question

What is the equation of a line passing through (-8, -3) and having a slope of
-4?

Answer 1

choices:
y = −4x + 20
y = 4x + 20
y = −4x – 35
y = 4x – 35
y = -4x + 4

Answer 2

y = −4x + 20
y = 4x + 20
y = −4x – 35
y = 4x – 35
y = -4x + 4

Answer 3

The equation of line having \((x_1, y_1)\) point and given slope is :

\[y - y_1 = m(x-x_1)\]

Here, \((x_1,y_1) = (-8,-3)\) and \(m = -4\), just plug in the values..

Answer 4

\[y - (-3) = -4(x - (-8)) \implies y + 3 = -4(x+8)\]

Answer 5

Solve right hand side by using Distributive property ie, distribute \(-4\) to the brackets and tell me what did you get?

Answer 6

y = −4x + 20

Answer 7

No, how you got that?

Answer 8

Can you show me your steps?