What polynomial has roots of -6, 1, and 4?

Question

jdoe0001 · Answer

$\large {
-6, 1, 4
\begin{cases}
x=-6\to x+6=0\to &(x+6)=0\
x=1\to x-1=0\to &(x-1)=0\
x=4\to x-4=0\to &(x-4)=0
\end{cases}\qquad thus
\ \quad \
(x+6)(x-1)(x-4)=\textit{original polynomial}
}$

thesmartone · Answer

And if you don't need it factored just multiply it all together and you should be getting something that starts with x^3

anonymous · Answer

i still don't really understand. 
here are the answer choices,
 x3 - 9x2 - 22x + 24

 x3 - x2 - 26x - 24

 x3 + x2 - 26x + 24

 x3 + 9x2 + 14x - 24

thesmartone · Answer

http://www.wolframalpha.com/input/?i=%28x%2B6%29%28x-1%29%28x-4%29

thesmartone · Answer

It is C...

anonymous · Answer

Thank you so much!

anonymous · Answer

how to i give you a medal? lol

thesmartone · Answer

There should be a button next to my response like this http://prntscr.com/4xunzq