Question

A diver running 2.5m/s drives out horizontally from the edge of a vertical cliff and 3.2s later reaches the water below. How high was the cliff ?

Answer 1

i'm not sure but i think you can just use \[d=v_{0}t+\frac{1}{2}at^2\]

Answer 2

should I consider the direction of gravity?

Answer 3

uhh... guess so for orientation purpose.

Answer 4

so i'm getting -50.176. so the cliff's height is 50.2 meters. assuming what i said was correct.