Question

Hey can some one help me its a easy question but i seem to not get something so i have to find value of t.

[2 / (t-3) ] + [1 / (t+4)] =0

2t+8+t-3 / (t-3) (t-4)=0

Answer 1

is this a system of equations? or is this part of your own attempt?

Answer 2

Its is my attempt the second line the first line is question and we have to find t value

Answer 3

[2 / (t-3) ] + [1 / (t+4)] =0

multiply thru by say (t+4)

[2(t+4) / (t-3) ] + 1 =0

multiply thru by (t-3)

2(t+4) + 1(t-3) =0

Answer 4

distrbute, and collect your like terms

Answer 5

in your attempt, realize that a fraction is equal to 0 if the top is equal to 0 ... and the bottom isnt 0

0/n = 0 for some nonzero n

Answer 6

I didnt get it where u got + 1 from in third line

Answer 7

[2 / (t-3) ] + [1 / (t+4)] =0

multiply thru by say (t+4) <------

[2 (t+4)/ (t-3) ] + [1 (t+4)/ (t+4)] =0(t+4)

[2 (t+4)/ (t-3) ] + 1 =0

Answer 8

since t+4 is not zero .... its on the bottom of a fraction to start with ... we can multiply thru and cancel it out

Answer 9

if we use your method:

2t+8+t-3 / (t-3) (t-4)=0 only if the top part is 0 soo

2t+8+t-3 = 0