The unknown solution is prepared by transferring 500.0 micro L into a test tube and adding the BCA working reagent solution and DI water. The final volume in the test tube is 3.00 ml. What dilution factor is applied when calculating the protein concentration of the unknown solution?

a) 8.33
b) 333
c) 6.00
d) 1.00

Question

The unknown solution is prepared by transferring 500.0 micro L into a test tube and adding the BCA working reagent solution and DI water. The final volume in the test tube is 3.00 ml. What dilution factor is applied when calculating the protein concentration of the unknown solution?

a) 8.33 
 b) 333 
 c) 6.00 
 d) 1.00

preetha · Answer

Initial volume is 500 micro L and it gets diluted to 3mL.  What is 500 microL/3 mL?  Convert the units to ml first.

anonymous · Answer

so 500microL = 0.5mL 
0.5/3= 0.1666 
doesn't make sense to me, help? @Preetha

australopithecus · Answer

C1V1=C2V2

or you can realize that when diluting something concentration decreases. So if you are determining the original concentration it should larger. so yes the ratio you set up doesn't make sense. Have you tried flipping it?

C1 = (V2/V1)*C2

Where,

C1 is original concentration
C2 is diluted concentration
V2 is volume of diluted
V1 is volume of undiluted

anonymous · Answer

@Australopithecus still dont know what to do

anonymous · Answer

@Australopithecus i understand your concept but i dont know how to apply this to my problem

anonymous · Answer

shoul i just do 3/.5 = 6 ?

anonymous · Answer

thanks guys answer is 6