use the fact that logb6=1.2925 and logb3=.7925 evaluate logb(1/2)^1/4. show how you used law of logs.

Question

adamaero · Answer

anonymous · Answer

this doesn't answer the question.

adamaero · Answer

anonymous · Answer

i don't understand where you're getting log 5 and log 42?

adamaero · Answer

It was an example. Sometime it's good to learn by example, but the numbers were not about your problem.
Anyway, 3/6 is 1/2.

anonymous · Answer

i understand the 3/6=1/2, my problem is the 1/4 exponent...so what you're saying is that i do this: (1.2925/.7925)^1/4

anonymous · Answer

accidently flipped the numbers: (.7925/1.2925)^1/4

anonymous · Answer

hello?

adamaero · Answer

Oh, didn't see it there. A property of logarithms is that you can pull the exponent down in front as a constant: 
(1/4)*...

adamaero · Answer

anonymous · Answer

so, 1/4logb(1/2)?

anonymous · Answer

then 1/4(logb1-logb2)

anonymous · Answer

right? wrong?