Mathematics
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OpenStudy (anonymous):
if x^2=27 what is the value of x^4/3?
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OpenStudy (fibonaccichick666):
so first, do you know what x^(4/3) means?
OpenStudy (anonymous):
Well, first find the value of x, and then substitute it in for the x in the next problem!
OpenStudy (fibonaccichick666):
(I'm assuming no calculators are allowed, though both approaches work)
OpenStudy (gorv):
x^4=(x^2)^2
OpenStudy (gorv):
orx^4=x^2*x^2
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OpenStudy (gorv):
i think u can proceed now??
OpenStudy (gorv):
@dawnum08
OpenStudy (anonymous):
i don't understand...how does that relate to x^2=27?
OpenStudy (anonymous):
well, you know it is basically saying x times itself equals 27.. think which number times itself equals 27
OpenStudy (fibonaccichick666):
can you explain what x^(4/3) means irst, then I promise I'll explain how it relates
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OpenStudy (anonymous):
i think i have it, x^2=27, take the square root of both sides you get x=+-3(squareroot of 3), plug both of those in for x in x^4/3?
OpenStudy (fibonaccichick666):
no, that would be the cubed root
OpenStudy (anonymous):
how do you write a square root symbol on a keyboard?
OpenStudy (fibonaccichick666):
please, first, what does x^(4/3) mean
OpenStudy (fibonaccichick666):
I apologize, I missed your parentheses, thst is correct but much harder than necessary
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OpenStudy (fibonaccichick666):
so please, first, tell me what x^(4/3) means
OpenStudy (anonymous):
i don't understand what you're asking? it means just what it says x to the 4/3 power.
OpenStudy (anonymous):
4/3 is the exponent.
OpenStudy (anonymous):
hello?
OpenStudy (fibonaccichick666):
right, but let's say you had 2^(4/3) how would you compute that?
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OpenStudy (fibonaccichick666):
without putting it into a calculator
OpenStudy (fibonaccichick666):
ie. what does a rational exponent mean?
OpenStudy (anonymous):
i don't know.
OpenStudy (fibonaccichick666):
once you know about them, it should click as to what @gorv was hinting at with his/her information
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OpenStudy (anonymous):
i'm confused, is my answer wrong?
OpenStudy (fibonaccichick666):
Yes.
OpenStudy (gorv):
\[x^{\frac{ 4 }{ 3 }}=(x^{4})^{\frac{ 1 }{ 3 }}=(x^2*x^2)^{\frac{ 1 }{ 3 }}\]
OpenStudy (fibonaccichick666):
Now, did you read the website?
OpenStudy (fibonaccichick666):
if you did, what gorv did ^^ should make sense
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OpenStudy (anonymous):
x^4/3 = the cube root of x^4, i get that
OpenStudy (fibonaccichick666):
ok, so, do you understand that\( x^4 =x^2x^2\)
OpenStudy (fibonaccichick666):
and can you tell me why?
OpenStudy (anonymous):
yes, i understand (27*27)^1/3
OpenStudy (fibonaccichick666):
ok, so, can you simplify that? (1 number)
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OpenStudy (fibonaccichick666):
then you are done. It wanted the value of \(x^{4/3}\) not the value of x.
OpenStudy (anonymous):
thank you.
OpenStudy (fibonaccichick666):
np