Question

Kari and Samantha have determined that their water-balloon launcher works best when they launch the balloon at an angle within 3 degrees of 45 degrees. Which equation can be used to determine the minimum and maximum optimal angles of launch, and what is the minimum angle that is still optimal?

a. |x – 3| = 45; minimum angle: 42 degrees
b. |x – 3| = 45; minimum angle: 45 degrees
c. |x – 45| = 3; minimum angle: 42 degrees
d. |x – 45| = 3; minimum angle: 45 degrees

Answer 1

@nermaljean99

Answer 2

Uhh what class is this for?

Answer 3

Algebra . Solving Absolute Value Equations

Answer 4

Algebra 1 or 2? and what lesson?

Answer 5

x is min/max angle.

The min angle would be the angle that's 3 deg smaler than 45 deg.
\[x_{\min} = 45 - 3 = 42\]which eliminates b and d.

If you now insert x_min in the two remaining equations which one is true?

Answer 6

So C ?

Answer 7

Yes!