Question

Can you help me understand my trig homework? (I'll fan and medal)

Answer 1

cos(x-5pi/4)=-sqrt2/2(cosx+sinx)

Answer 2

so... you're looking for "x"?

Answer 3

\(\Large \bf cos\left(x-\frac{5\pi}{4}\right)=-\cfrac{\sqrt{2}}{2}\) right?

Answer 4

well i'm pretty sure x is also theta, because that's what my teacher said, but i think what you are suppose to do is prove that each side equals each other

Answer 5

after the -\[\sqrt{2/2} is (cosx+sinx)\]

Answer 6

hmm missing info there... one sec \(\Large \bf cos\left(x-\frac{5\pi}{4}\right)=-\cfrac{\sqrt{2}}{2cos(x)sin(x)} ?\)

Answer 7

the only thing in the denominator is the 2 though

Answer 8

\(\bf cos\left(x-\frac{5\pi}{4}\right)=-\sqrt{\cfrac{2}{2cos(x)sin(x)}} ?\)