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Calculus1
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(y/x)+(x/y)=2y calculate the derivative respect to x (implicit differentiation)
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use quotient rule for each of the fractions http://en.wikipedia.org/wiki/Quotient_rule each time you differentiate a "y" term, multiply by dy/dx
this is going to be a drag, but we can do it if you like
\[(lowdhigh-highdlow)/low ^{2}\]
\[(x(dy/dx)-y(1))/x^2 + (y(1)-(x)(dy/dx))/y^2=2(dy/dx)\] \[(x(dy/dx)-y)y ^{2}+(y-x(dy/dx))x ^{2}=2x ^{2}y ^{2}(dy/dx)\] \[xy ^{2}(dy/dx)-y ^{3}+x ^{2}y-x ^{3}(dy/dx)=2x ^{2}y ^{2}(dy/dx)\] \[dy/dx(xy ^{2}-x ^{3}-2x ^{2}y ^{{2}})=y ^{3}-x ^{2}y\] \[dy/dx=(y ^{3}-x ^{2}y)/xy ^{2}-x ^{3}-2x ^{2}y ^{2}\] then just reduce/factor out x's and y's
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