Local behavior questions! picture attachment below!
@jim_thompson5910 hey! you helped with my other questions, any chance you know about this stuff too?
f(x) = x^3 - 6x^2 what is f ' (x) ?
hmm im not sure..you dont plug in 0 do you?
have you learned about derivatives?
that word doesnt sound familiar but i think we have!! hah
is this calculus class?
no it is classified as advanced algebra but it sure seems like calculus material. i just did the problem, would the answer be D?
this is definitely an unfair problem if you haven't learned about calculus and derivatives
yes ive never taken any calculus class. this material is all new.
but we can at least use the graph
yes thats what i did!
notice how the graph continues on forever as you go down the left side so there is NO global min
at the same time, the graph continues on forever as you go up the right side so there is NO global max
there are no global extrema
however, there is a peak at x = 0 so this is where the local max is there is a valley at x = 4 which is where the local min is
there are no global extrema but there are 2 local extrema (1 local max and 1 local min)
ahh so it would be B. i have a hard time telling the difference between global and local max/min.
global refers to the entire domain unless otherwise explicitly stated
local is just within a very specific interval (usually a small interval)
yes B
thank you! i have some others, would you be able to check my answers? if you dont have time thats fine!
sure I can do that
awsome! thank you. here is another. im not positive on my answer.
its just telling you to find the polynomial function that goes with the graph. i know the leading coefficient cant be a negative number so that left me to A and B.
actually im positive it must be A! i just checked again.
lol forget about that. i dont know why im so stupid. okay i will send you the next one that im actually unsure about!
choice A is correct
you aren't stupid
haha i may not be stupid but i was just acting stupid! i should have known. thank you though. here is one i am unsure about. you have to factor first right?
im bad with these types of questions where you have to factor.
yes factor as much as you can
tell me what you get
hmm 2x^2(6+x) (-6+x)?
very good
you can also write it as 2x^2(x+6)(x-6)
2x^2(x+6)(x-6) = 0 2x^2 = 0 or x+6 = 0 or x-6 = 0 solve each equation for x
Okay, so now the answer i get would be B! it has to be because 2x^2=0 is going to be 0 and it is going to be touch. and there are still the other two equations so it has to be B right?
correct
even multiplicity ----> touch odd multiplicity ----> cross
perfect thanks! and this is the last one. im pretty sure im right, just want to make sure though.
did you graph this function?
i did. it only has one turning point
yes, notice how it peaks out at (12.5, 156.25) this is the highest the graph goes...for the ENTIRE domain. So this is both a local max and a global max
there is no local min or no global min because it continues on forever downward
ohhh okay. so the answer would be D.
good
thank you!! you explained it really well. that was the last question i was unsure about! thank you again!
no problem
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