Question

Find the general solution of the equation dy/dt= ty^2 t/t^2+1

Answer 1

\[\frac{dy}{dt}=\frac{ty^2}{t^2+1} ?\]

Answer 2

I could be seeing this wrong because I do see another t on top also

Answer 3

you could do this problem by separation by variables

Answer 4

Yea there another t on top. I dont know how to separate it

Answer 5

Dy/dt=(ty^2 t)/(t^2+1)

Answer 6

\[\frac{dy}{dt}=\frac{t^2y^2}{t^2+1} \\ dy=\frac{t^2y^2}{t^2+1}dt \\ \frac{1}{y^2}dy=\frac{t^2}{t^2+1} dt \]

Answer 7

integrate both sides

Answer 8

it could be
\(y^2(t)\)
which means square of y(t)
but the approach remain same :)

Answer 9

hmm... That could be true. I thought the extra t was a bit odd.