Question

Liquid A has 10 grams of element X per liter. Liquid B has 15 milligrams of element Y per cm^3 (there are 1000 milligrams in a gram and 1000 cm^3 in a liter). It is desired to make 120 grams of molecule Z. To make 18 grams of Z requires 2 grams of X and 16 grams of Y. How many liters of each liquid should be used?

Answer 1

FIrst how many grams of x and y do we neeed
18gz=2gx+16gy

120gz=(120/18)2gx+(120/18)16gy

Answer 2

then figure out how much liquid a and liguid b

A --> (10gx/L)
B --> (15mgY/cc)(1000cc/L)(1g/1000mg)

Answer 3

so these two equations need to be solved?

Answer 4

no.

Answer 5

We had a receipe that yields 18grams of z. I scaled that up to yield 120grams of z

Answer 6

now we have A and B in the proper units (grams/Liter)

Answer 7

to make 120grams of z we need (120/18)2 grams of x and we need (120/18)16 of y

Answer 8

Now I can figure out how much liquid A is needed.
((120/18)2 grams of x) (1 liter of A/10grams of x) = ( ) liters of A

Answer 9

same thing for liquid B.
make sense?

Answer 10

oh ok!