A sector is formed if a part of a circle is cut off from the center of a circle. It can then be used to form a cone if you glue the two radii together. For any given sector, the cone thus formed is unique. This means that both the surface area and the volume can be expressed in terms of variable theta (in radian) and R. Based on the diagrams, what is the relationship between R and L. The answer is R = L. The question after is express r in terms of theta and R. I've put r = R / theta but I'm sure that's wrong.
http://www.mathwarehouse.com/solid-geometry/cone/images/volume-cone-formula-vs-cylinder-base.png
\(\Huge\bf \color{green}{Welcome~to~OpenStudy!!}\hspace{-310pt}\color{cyan}{Welcome~to~OpenStudy!!}\hspace{-307.1pt}\color{purple}{Welcome~to~\color{purple}{Open}}\color{purple}{Study!!!!}\) Intense, do you still need help?
seriously, how do you do that kind of text?
yes but it's for a different question. it says express r in terms of theta and R. It's based off of the picture i uploaded. I put r = R/theta
It's called LaTeX in the LaTeX section:) You just gotta learn the codes and that kinda stuff.
Can you take a screenshot? I feel like something is missing.
Those two picture are the only ones on the sheet. Here's what the message says: A sector is formed if a part of a circle is cut off from the center of a circle. It can then be used to form a cone if you glue the two radii together. For any given sector, the cone thus formed is unique. This means that both the surface area and the volume can be expressed in terms of variable theta (in radian) and R. Based on the diagrams, what is the relationship between R and L. The answer is R = L. The question after is express r in terms of theta and R. I've put r = R / theta but I'm sure that's wrong.
What is the length of the sector of radius R and central angle \(\theta\)?
There was no length given. They just want a general equation for r
The arc length of the sector of radius R and central angle \(\theta\) is R\(\theta\) where \(\theta\) is in radians. This arc length becomes the circumference of the circle that forms the base of the cone. Therefore, \(2\pi r = R\theta\). \(\Large r = \frac{R\theta}{2\pi}\)
:D Thanks! The next questions require me to find area of the sector, lateral area of the cone, and the height of the cone. I would just have to substitute \[r = R \theta / 2\pi\]
@aum for finding the area of a sector, could i substitute \[r=R ^{2}\theta ^{2} \div 2\] for \[\pi \times r^{2}\]? I got \[A=R^2\theta^2/4\pi \] Would that be right?
I mean \[r = R^2\theta^2 / 2\pi\]
Area of the sector = \(\large \frac 12 R^2 \theta\).
Lateral Surface Area of the cone = \(\large \pi r L = \pi * \frac{R\theta}{2\pi} * R = \frac 12 R^2 \theta\)
How did you get 1/2 for the area?
Which one: sector or lateral surface area ?
Sector. Did you substitute it into 2 * pi * r?
That is the standard formula for area of a sector: \(\large \frac 12 R^2 \theta\)
Ok thanks and for the lateral surface area of the cone, 1/2 *R^2* theta is the result when everything has been simplified? It is the same as the area, right?
correct. The standard formula for the lateral surface area of a cone is pi * r * L. I substituted r in terms R and L = R, simplified it and it came out to be the same as the area of the sector as expected.
:D THANK YOU AUM!
You are welcome.
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