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Mathematics 15 Online
OpenStudy (anonymous):

HELP ME PLEASEEE???!!!??? FAN & MEDAL! Polygon ABCD will be dilated by a scale factor of 2.2 with the origin as the center of dilation, resulting in the image A'B'C'D'. What will the slope and length of C'D' be? A. m = undefined, C'D' = 13.2 units B. m = 0, C'D' = 6.6 units C. m = 0, C'D' = 13.2 units D. m = undefined, C'D' = 8 units

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8 ??

OpenStudy (anonymous):

@skullpatrol @hba ??

OpenStudy (anonymous):

@iGreen @anonymous_user ??

OpenStudy (igreen):

Multiply 2.2 to points C and D.

OpenStudy (anonymous):

A. m = undefined, C'D' = 13.2 units

OpenStudy (anonymous):

Okay(: Are you sure @CO_oLBoY ? (:

OpenStudy (anonymous):

i think so

OpenStudy (anonymous):

Okay. I just dont want to get it wrong and fail it.

OpenStudy (anonymous):

wait i'll check it again then

OpenStudy (anonymous):

okay thank you.

OpenStudy (igreen):

C = (10, 6) D = (10, 12) 2.2 * 10 = 22 2.2 * 6 = 13.2 2.2 * 12 = 26.4 So we have: C' = (22, 13.2) D' = (22, 26.4) Line CD and C'D' will be the same but parallel.. And since CD is a straight line, then it will be undefined. To find the distance between two points use the formula: \(\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\) Here: \(x_2 = 22\) \(x_1 = 22\) \(y_2 = 26.4\) \(y_1 = 13.2\) \(\sqrt{(22-22)^2 + (26.4-13.2)^2}\) \(\sqrt{(0)^2 + (26.4-13.2)^2}\) \(\sqrt{(0)^2 + (13.2)^2}\) \(\sqrt{0 + 174.24}\) \(\sqrt{174.24}\) \(13.2\)

OpenStudy (anonymous):

yup its A. m = undefined, C'D' = 13.2 units

OpenStudy (anonymous):

Yay(: Okay! THANKS BOTH OF YOU! I wish i could give you both medals.

OpenStudy (anonymous):

np :) and no need to give me a medal :)

OpenStudy (anonymous):

Its okay. I did anyways. (:

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