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find the derivative of f(x)= log5(3(x^4+5)^8)/tan(3x^2) (Do not simplify!) (Step by step) WILL FAN AND MEDAL!!
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\[f(x)=\log_{5}(3(x ^{4}+5)^{^{8}})\div \tan(3x ^{2}) \]
\[the derivative of \log is \log_{b} u=du/u \ln b\] so the derivative of the log thing on top \[(24(x ^{4}+5)^{7}(4x ^{3}))/(3(x ^{4}+5)^{8}*\ln5\]
derivative of tan(3x^2) is \[\sec ^{2}(3x ^{2})*(6x)\]
do the quotient rule lowdhigh-highdlow all over low squared
so its tan(3x^2)(derivative of the log thing)-(log thing)(derivative of tan) all over the tan thing squared
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