Question

Write the equation of the line that is tangent to the circle (x + 6)2 + (y + 4)2 = 25 at the point (-9, -8).


y=4/3x−593

y=−34x+593

y=4/3x+594

y=−3/4x−594

Answer 1

Write the equation of the line that is tangent to the circle (x + 6)2 + (y + 4)2 = 25 at the point (-9, -8).


y=4/3x−59/3

y=−3/4x+59/3

y=4/3x+59/4

y=−3/4x−59/4

Answer 2

You need a `point` and `slope` to write the equation of line

Answer 3

you already have a `point` (-9, -8)

Answer 4

any ideas how to find the slope of the required tangent ?

Answer 5

the 593 are suposeed to be 59/3 and 59/4

Answer 6

no i domnt im confused

Answer 7

see if you can use the fact that \(\large \text{tangent} \perp \text{radius}\)

\

Answer 8

start by finding the slope of that radius segment

Answer 9

it ends in : (-6, -4) and (-9, -8)
slope = ?

Answer 10

i got y= 3/4x - 59/4

Answer 11

D.

Answer 12

doesnt look correct

Answer 13

either that or B

Answer 14

nope

Answer 15

did you find the slope of radius segment yet ?

Answer 16

no

Answer 17

interesting, how did you figure out its either D or B ?

Answer 18

im guessing good guesser

Answer 19

guessing is okay if it works

Answer 20

yes i got it right my answer is indeed correct sir

Answer 21

okay good for you