Question

3x3y + 12xy - 3x2y - 12y

Part A: Rewrite the expression so that the GCF is factored completely. (3 points)

Part B: Rewrite the expression completely factored. Show the steps of your work. (4 points)

Part C: If the two middle terms were switched so that the expression became 3x3y - 3x2y + 12xy - 12y, would the factored expression no longer be equivalent to your answer in part B? Explain your reasoning. (3 points)

Answer 1

I'll give you a medal if i get just the answer for a b and c

Answer 2

@Quinn.Lavnt @Abhisar @anonymous_user @AnswerMyQuestions @Auxuris @animal_lover36 @ashley1211 @ZnappyDooZ @wally15 @Squirrels @Skyz @shereenkhan @swaggd2 @Samus_Aran @sammie2017 @EmogirlAtEmoooocow @edmodo @em0ney @Elsa213

Answer 3

\(\large \begin{align} \color{black}{\text{is it this }\\~\\
3x^3y + 12xy - 3x^2y - 12y}\end{align}\)

Answer 4

eah thats it

Answer 5

Final result :
3y • (x2 + 4) • (x - 1)
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 1 more similar replacement(s).

Answer 6

all i see are ?????????????? i am lost o.0

Answer 7

refresh page

Answer 8

okay so whats A B and C on that i think 3y(^2+4)(x-1) is the GCF right? idk xD sorry

Answer 9

i am kind of slow...

Answer 10

3x3y + 12xy - 3x2y - 12y
= 9xy + 12xy - 6xy - 12y
= 9xy + 6xy - 12y

Answer 11

thats part a?

Answer 12

= 15xy - 12y
GCF of 15xy and 12y is 3y

Answer 13

and we get this 3y(5x - 4)

Answer 14

that's all :)

Answer 15

so that all A B and C?

Answer 16

\(\large \begin{align} \color{black}{
A.)\\~\\
3x^3y + 12xy - 3x^2y - 12y\\~\\
\text{u have to write it such that}\\~\\
\text {their must be a common factor among all}\\\\~\\
=3y(x^3+4x-x^2-4)\\~\\
\text{3y is the common factor here}}\end{align}\)

Answer 17

ooooh ok ty so much lets move on to B now :)

Answer 18

u take me wrong @ SouthernRebel101

Answer 19

i mean to say that's it.

Answer 20

\(\large \begin{align} \color{black}{\\~\\
B.)~\\~\\
=3y(x^3+4x-x^2-4)\\~\\
\text{for B.) u have to factor it completly}\\~\\
=3y[x(x^2+4)-(x^2+4)]\\~\\
=3y[(x^2+4)(x-1)]}\end{align}\)

Answer 21

the last one is the final answer?

Answer 22

for B right?

Answer 23

\(\large \begin{align} \color{black}{\\~\\
C.)~\\~\\
=3x3y - 3x2y + 12xy - 12y\\~\\
\text{is same as }\\~\\
\color{red}{=3x3y + 12xy- 3x2y - 12y}\\~\\
\text{so exhanging the middle term }\\~\\
\text{won't let any change in the answer }\\~\\
\text{the answer will be the same}}\end{align}\)

Answer 24

TY