In the figure below, segment CD is parallel to segment EF and point H bisects segment DE:

Prove ΔDIH ≅ ΔEGH.

Question

In the figure below, segment CD is parallel to segment EF and point H bisects segment DE:

Prove ΔDIH ≅ ΔEGH.

anonymous · Answer

The figure.

anonymous · Answer

I will fan and medal. 

All I need is a little help starting the proof and from there I can figure it out on my own. Thanks!

anonymous · Answer

This is a lot of explaining to do lolz

anonymous · Answer

Haha, any help at all is appreciated!

anonymous · Answer

Does this make sense?

DH=EH                                     Definition of a Bisector
Angle IDH = angle GEH             Alternate interior angles 
Angle DHI = angle EHG             Vertical angles are congruent
Triangle DIH = Triangle EGH     ASA postulate

anonymous · Answer

Yes it does! I was trying to figure out how to write it in a way my teacher would understand!

anonymous · Answer

Thank you!

anonymous · Answer

No worries! It's very helping keeping those theorems memorized or at least nearby.

anonymous · Answer

Writing out proofs is my weakness in geometry, once it is partially written or If I'm given the parts of the proof to sort into the right places everything clicks like with this. Thank you.